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To graph the quadratic function f(x)=x²+8x+10, I already rewrote it in vertex form f(x)=(x+4)²−6, so we know the minimum value is -6 at x=-4. Using the quadratic formula, the x-intercepts are x = -4 ± √6, and since √6 is between 2 and 3, that places the larger x-intercept roughly between −1 and −2. The y-intercept is 10, so we plot ...
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